I think the issue is that the typedef is intended to hide the smartptrness so it...

ben0x539 on Nov 23, 2012 | parent | context | favorite | on: Rule of Zero (C++)

I think the issue is that the typedef is intended to hide the smartptrness so it's not obvious what the API for getting an old-style pointer is, or whether getting an old-style pointer is even part of the intended public interface anymore (beyond p.operator->() anyway ;)