Those compute the same value, but I think the point of the C++ stream version is to compute the value using a lazily evaluated infinite list.

The C++ equivalent of your Python would be something like:

    typedef boost::counting_iterator<int> ci;
    auto sum = std::accumulate(ci(0), ci(10), 0, [](auto x, auto y) { return x + (y*y); });

No special streaming library required.

A solution in the spirit of the post using itertools:

    >>> from itertools import islice,count
    >>> sum(x*x for x in islice(count(1),10))
    385